144+72x-16x^2=0

Solution for 144+72x-16x^2=0 equation:

144+72x-16x^2=0

a = -16; b = 72; c = +144;
Δ = b2-4ac
Δ = 722-4·(-16)·144
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-120}{2*-16}=\frac{-192}{-32}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+120}{2*-16}=\frac{48}{-32}
=-1+1/2
$